Home

An object of mass 200 kg is accelerated uniformly

an object of mass 200 kg is accelerated uniformly from 10 metre per second to 20 metre per second in 2 seconds. calculate the initial and final Momentum - 2059800 An object of mass 200kg is accelerated uniformly from a velocity of 10 m/s to 20 m/s in 5 seconds . Calculate the initial and final momentum of the object. also find the magnitude of the force exerted on the object

an object of mass 200 kg is accelerated uniformly from 10

The weight of an object of mass 2 kg at (c) 600 N (d) 475 N a point on the earth's surface when the gravitational field is 10 N/kg is: A ball of mass 0.5 kg is tied to a thread and rotated at a constant angular velocity of(a) 20 N (b) 0.2 N 10 rad/s in a circle of radius 1 m The Questions and Answers of An object of mass 50kg is accelerated uniformly from a velocity of 4m/s to 8m/s in 8s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.? are solved by group of students and teacher of Class 9, which is also the largest student community of Class 9 Jul 09,2021 - An object of mass 100 kg is accelerated uniformly from a velocity of 5 M per second 28 M per second in 6 second calculate the initial and final momentum of the object also find the magnitude of the force exerted on the object? | EduRev Class 9 Question is disucussed on EduRev Study Group by 148 Class 9 Students An object of mass `100kg` is accelerated uniformly from a velocity of `5m//s` to `8m//s` in `6 s`. Calculate the initial and final momentum of the object. Also, find the magnitude of the exerted on the object

00 cm and mass 200 kg it starts from rest and. A grinding wheel is in the form of a uniform solid disc of radius 7.00 cm and mass 2.00 kg. It starts from rest and accelerates uniformly under the action of the constant torque of 0.600 N.m that the motor exerts on the wheel an object of mass 100kg isn accelerated uniformly from a velocity of 5m/s to 8m/s in 6s.calculate the initial and the final momentumof the object.also find the magnitude of force exerted on the body An object of mass 100 kg is accelerated uniformly from a velocity of 5 m s^{-1} to 8 m s^{-1} in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms -1 to 8 ms -1 in 6 s. Calculate the initial and final momentum of the object. Also find the magnitude of the force exerted on the object Q16 ) An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object

An object moves in uniform circular motion at 25m/s and takes 1.0 second to go a quarter circle, calculate the centripetal acceleration. 39 m/s^ 2. Calculate the speed with which the moon orbits the earth given the distance from earth to moon as R = 3.84 · 108 m. (Astronomers note that the true orbital period of the moon, is 27.3 Earth days An object of mass 10 g is sliding with a constant velocity of 2 mf s on a frictionless horizontal table. The force required to keep the object moving with the same velocity is. (a) 0N. (b) 5N. (c) 10 N. (d) 20 N. Solution (a) Question 9) A cricket ball of mass 0.20 kg is moving with a velocity of 1.2m/s

At a point between the two objects at a distance d from the 500-kg objects, the net force on the SCI Il-kg object will be zero when G (san kg) (200 kg) G kg) (500 kg (a Acom 0245m A 200-kg object and a 500-kg object are separated by 0.400 m. (a) Find the net gravitational force exerted by these objects on a 50.0-kg object placed midway between. An object of mass 100 kg is accelerated uniformly from a velocity of 5m s-1 to 8m s-1 in 6s Calculate the initial and final momentum of the object also find the magnitude of the force exerted on the object - Science - Periodic Classification of Element Mass of loaded truck, m2 = 2000 + 2000 = 4000 kg. Acceleration, a2 = ? m1×a1 = m2×a2. a2 = 0.25 m/s 2. Multiple Choice Questions. Q41. The rockets work on the principle of conservation of: a) mass. b) energy. c) momentum. d) velocity. Answer: The correct answer is c) momentum. Q42. An object of mass 2 kg is sliding with a constant velocity of.

An object of mass 200kg is accelerated uniformly from a

A race car has a mass of 710 kg. It starts from rest and travels 40 meters in 3.0 seconds. That car is uniformly accelerated during the entire time. What net force is applied to it? 40 m 0 m s-1 ---? 3 s = +1 2 2 40=1 2 ()(3)2 =8.89m −2 = =(710)(8.89) =6311 A) the straight-line distance between the centers of the two masses. B) the rate at which both objects are moving. C) the radius of the first mass. D) the radius of the second mass. A car is moving down a freeway in a straight line at a constant rate of 20.0 m/s for 4.0 s. Its acceleration is Use the formula from Newton's second law. F = ma, where F = force (N), m = mass (kg), and a = acceleration (m/s²) Calculate the force. F = 50 kg × 5 m/s² = 250 kg•m/s² = 250

The mechanical system is used to facilitate the lifting of very massive objects. Question: A system consisting of a disk with a radius of 50 cm, with a uniformly distributed mass of 10 kg. It acts similar to a pulley when a wire of negligible mass is wound onto a small cylinder with a radius of 10 cm, of the same material as the larger disc and. uniformly accelerated motion s = ut + 2 2 18 An object of mass 0.30 kg is thrown vertically upwards from the ground with an initial velocity of 200 kg steel wires steel wires platform The wires obey Hooke's law when a load of mass 200 kg is placed on the platform. A A? . . What is the force required to accelerate an object with a mass of 20 kg from stationary to 3 m/s 2? F = m * a. F = 20 kg * 3 m/s 2. F = 60 N. Newtons are a derived unit, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared. Further Readin This force, mass, and acceleration calculator is based on one of the most fundamental formulas in physics, namely: F = m a. where F = Force m = Mass a = Acceleration This formula allows you to calculate the force acting upon an object if you know the mass of the object and its rate of acceleration

An object of mass 100 kg is accelerated uniformly from a

  1. A uniform square object of mass m = 2.00 kg and dimension a = 0.250 m comes under action of forces, F_1 = 2.00 N, F_2 = 4.00 N, F_3 = 2.00 N, and F_4 = 4.00 N, applied in the plane of the object to the corners and making consecutively angles of 90 degree, 60 degree, 30 degree and 0 degree with the side of the square
  2. An object of mass 100 kg is accelerated uniformly from a velocity of 5 m s-1 to 8 m s ' in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object. Solution: Question 17
  3. An object of mass 100 Kg is accelerated uniformly from a velocity of 5ms-1 to 8ms-1 in 6s. Calculate the initial and final momentum of the object. Also find the magnitude of the force exerted on the object. Answer: Mass of the object, m = 100 Kg Initial velocity, u = 5 ms-1 Final velocity, v = 8 ms-2 (i) Initial momentum = mv = 100 × 5 = 500.
  4. Q.20: An Object of mass 100 kg is accelerated uniformly from a velocity of 5 ms-1 to 8 ms-1 in 6 sec. Calculate the initial and final momentum of the object. Also find the magnitude of the force exerted on the object
  5. g all of the mass of each object is located at the point shown for each, calculate the moment of inertia of this system. A) 1.3 kg • m2 B) 3.1 kg • m2 C) 5.3 kg • m2 D) 7.2 kg • m2 E) 9.1 kg • m2 Page
  6. An object that is moving in a linear path with an acceleration in the direction opposite to the motion has a(n) _____ velocity. decreasing On a trip, a family travels 200 km in 2.5 h on the first day, 300 km in 4.0 h on the second day, and 250 km in 3.5 h on the third day

MCQ Questions for Class 9 Science: Ch 9 Force and Laws of Motion. 1. A plate, a ball and a child all have the same mass. The one having more inertia is the. 2. The inertia of an object tends to cause the object. 3. The rate of change of momentum with respect to time is measured in. 4 b) An object of mass 16 kg is moving with an acceleration of 3 m/s 2. Calculate the applied force. If the same force is applied on an object of mass 24 kg, how much will be the acceleration? (Ans: 48 N, 2 m/s 2) Answer: The force acting on the 1 body is 48 N and the acceleration of the 2 body is 2 m/s Apr 14, 2008. #3. trex said: I need to calculate the force of gravity on earth of an object that has a mass of 200 kg. Try F = Gmm/r^2 where G = the universal gravitational constant, M = the earth's mass, m = the mass of the object and r = the distance between the centers of each mass What is the mass of the object? (1) 64 kg (2) 20 kg (3) 12 kg (4) 4.0 kg 4. Base your answer to the following question on a 1-kg object moving at 200 m/sec (2) a 10-kg object moving at 30 m/sec (3) a 20-kg object moving at 20 m/sec A 1.2 x 103-kilogram car is accelerated uniformly from 10. meters per seconds to 20. meters per second in.

An object of mass 14 kg is placed at a certain height from the ground. If the potential energy of the object is 560 J, then find the height of the object with reference to the ground. (take g = 10 ms-2 A bullet of mass 200 g is fired from a gun of mass 10 kg with a velocity of 100 m/s. Calculate the velocity of recoil. Answer: An object remains in a state of rest or of uniform motion along a straight line unless compelled to change that state by an applied force. Acceleration of an object if the mass of an object is 2 kg 3. The. An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms -1 to 8 ms -1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object A 2.00-kg object is attached to a spring and placed on a horizontal, smooth surface. A horizontal force of 20.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest with an initial position of x

Where, m = mass of the body, g = acceleration due to gravity and h = height of the body. CALCULATION: Given that: Mass of the object, m = 20 kg, displacement (height), h = 2 m, and acceleration due to gravity, g = 10 m s -2. Potential Energy = mgh = 20×10×2 = 400 J. So option 2 is correct. Download Question With Solution PDF › 980. newtons, the mass of the object is A) 50.0 kg C) 490. N B) 100. kg D) 908 N 2. If a car is traveling at an average speed of 60 An object is uniformly accelerated from rest to a speed of 25 meters per second in 10 seconds. The acceleration of the object is A) 1.0 m/s 2 B) 2.0 m/s 2 C) l.5 m/s Newton's second law of motion says that the net external force on an object with a certain mass is directly proportional to and in the same direction as the acceleration of the object. Newton's second law can also describe net force as the instantaneous rate of change of momentum. Thus, a net external force causes nonzero acceleration Determine the angular acceleration on the object 2. If the object starts from rest, calculate the time needed to be in a vertical position 3. Determine the frequency of the object in RPM ; Question: Consider a uniform metal rod (uniform density with mass 25 kg). -3.0 m 60° 12 N 1.5 m 24 N Axis 1. Determine the angular acceleration on the object 2 On substitution using the above equation, it will be seen that the acceleration due to gravity on the 5 kg mass is 1.25G m/s2 while that on the 3 kg mass is 0.75G m/s2. This proves that mass directly affects the gravitational acceleration experienced on a body, i.e, the heavier the mass, the higher the gravitational acceleration felt

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity v and has the magnitude ac = v2 r;ac =rω2 a c = v 2 r; a c = r ω 2. The unit of centripetal acceleration is m/s 2 Ist object Given, Acceleration (a) = 20m/s 2 Let the mass of one body = m 1 And a force of 50N will be applied over it. We know that Force (F) = Mass (m) x Acceleration (a) ⇒ 50N = m 1 × 5ms-2 m 1 =50N/5ms-2 = 10kg 2nd Object. Given, Acceleration (a) = 20m/s 2 Let the mass of one body = m 2 And a force of 50N will be applied over it Truck with a mass of 2250 kg moving with a velocity of 25 m/s C) ith a mass of 1210 kg moving at a velocity of 51 m/s (e I C) c. Truck with a mass of 6120 kg moving at a velocity of 10 m/s (Q I / 'ZOO ) S d. Car with a mass of 1540 kg moving at a velocity of 38 m/s S 11. A rubber ball with a mass of 0.30 kg is dropped onto a steel plate Solution for If the mass of an object is 200kg and the applied force is 2600N, calculate the acceleration , Radius Of blender =5 cm speed=1 m/s mass of water =0.001 acceleration is given by v2/2 And Fo Unit of Force is Newton i.e kg.m/s2 here m = meter kg = k question_answer.

A force of 200 N acts tangentially on the rim of a wheel 25 cm in radius. Question 2 A neutron star is formed when an object such as our Sun collapses. Suppose a u 'form spherical star of mass M and radius R collapses to a uniform sphere of radius 10-5R. If the original star has a rotation rate of 1 rev each 25 days (as does the Sun), what. 10. A ball travels at 50 m/s. If the momentum of the object is 200 kg-m/s, what is the mass of the ball? 11. A 100 kg car accelerates uniformly from rest for a distance of 20 m in 10 s. An object with a mass of 2 kg is accelerated from rest. The graph below shows the magnitude of the net force as a 20. An object of mass 3 kg starts from. 4.6 m / s 2toward the center of the circle Correct, the acceleration is toward the center of the circle. Question 3 1 / 1 pts A satellite orbits the earth with a period 920 min. If the mass of the satellite is 2300 kg, what is the magnitude of the gravitational force between the earth and the satellite? 33.8 N 80.6 N 40.2 N 11.7 N Correct, you can use Kepler's third law of planetary motion. Which would require a greater force for accelerating a 2 kg of mass at 4 ms-2 or a 3 kg mass at 2 ms-2? Answer: We know, force F = ma Given m 1 = 2 kg a 1 = 4 ms-2 m 2 = 3 kg a 2 = 2 ms-2 F 1 = m 1 a 1 = 2 × 4 = 8 N F 2 = m 2 a 2 = 3 × 2 = 6 N ∴ F 1 > F 2. Thus, accelerating 2 kg mass at 4 ms-2 would require a greater force. Question 6

2. As the mass of an object decreases, its inertia will a. Decrease b. Increase c. Remain the same 3. The fundamental unit for a force of 1 N is a. m / s2 b. kg c. m / s2 / kg d. kg * m / s2 4. An object with a mass of 2 kg is accelerated at 5 m/s2. The net force acting on the mass is a. 5 N b. 2 N c. 10 N d. 20 N 5 An object with mass 40 kg accelerates at 9 m/s? under a constant net force. What must be the object's acceleration to the nearest 0.1 m/s2 if the mass is increased by an additional 20 kg while keeping the net force the same? Do not include units in your answer A sailboat has a mass of 1.50 x 10 3 kg and is acted on by a force of 2.00 x 10 3 N toward the east, while the wind acts behind the sails with a force of 3.00 x 10 3 N in a direction 45° north of east. Find the magnitude and direction of the resulting acceleration. Find the acceleration of the body of mass 10.0 kg shown below

NCERT Q16 - An object of mass 100 kg is accelerated

A body with uniform acceleration changes its speed by a constant value. Galileo proved that when objects are released simultaneously from a certain height, they reach the ground at the same time, regardless of their masses and air resistance. Galileo discovered that all objects fall with the uniform acceleration in vacuum Its angular velocity increases uniformly to 14 rad/s in 3 s. Find the rod's angular acceleration over this time period. If the 6.0 kg mass is 4.0 m away from the pivot, how far away is the 10.0 kg mass if the system is not rotating? mass is a measure of an object's acceleration in response to a force. What is the rotational analog. Find the gravitational potential energy of a body of mass 200 kg on the earth's surface. [M(earth) = 6 × 10 24 kg, R(earth) = 6400 km] Answer:-1.251 × 10 10 J. Question 11. Find the gravitational potential energy of a body of mass 10 kg when it is at a height of 6400 km from the earth's surface. [Given: a mass of the earth and radius of. Together, they have mass 200.0 kg. If the thrust of the motor is a constant force of 40.0 N in the direction of motion, and if the resistive force of the water is numerically equivalent to 2 times the speed v of the boat, set up and solve the differential equation to find: (a) the velocity of the boat at time t ; (b) the limiting velocity (the. an object of mass 0.5 kg is whirled at the end of string 0.8 m long if the string make three revolution in 1.2 sec find the tension of the string . phy. Review. An object with a mass of m 5 5.10 kg is attached to the free end of a light string wrapped around a reel of radius R 5 0.250 m and mass M 5 3.00 kg

Two constant forces act on an object of mass m = 5.00 kg object moving in the xy plane as . physics. An object of mass 200.0kg is moving from rest under the influence of net force 1.0Kn.Find the acceleration of the object and work done within 20.0s.What is the velocity of the object at the end of 20.0s interval of time The average speed is =204.2ms^-1 The kinetic energy is KE=1/2mv^2 The mass is m=5kg The initial velocity is =u_1ms^-1 The final velocity is =u_2 ms^-1 The initial kinetic energy is 1/2m u_1^2=75000J The final kinetic energy is 1/2m u_2^2=135000J Therefore, u_1^2=2/5*75000=30000m^2s^-2 and, u_2^2=2/5*135000=54000m^2s^-2 The graph of v^2=f(t) is a straight line The points are (0,30000) and (9. 3. A force of 45.0 N causes an object to travel in a circle with a diameter of 7.50 m with a frequency of 0.60 Hz. What is the mass of the object? (0.84 kg) 4. An object rotates around a circle of radius 4.75 m. If the object completes 15 cycles in 35 s, what is the centripetal acceleration? (34.4 m/s2) VII. Hand-in assignment 1 In a uniform gravitational ®eld, the center of mass and the center of gravity coincide. Solved Problems 8.1 An 8.0-g bullet is ®red horizontally into a 9.00-kg cube of wood, which is at rest, and sticks in it. The cube is free to move and has a speed of 40 cm/s after impact. Find the initial velocity of the bullet

The acceleration of an object moving along a circular path is given by: =v2/r towards the center of the circle. The centripetal force of an object moving along a circular pat h is given by: F=mv2/r. Example 1 . A 4.0 kg object is traveling in uniform circular motion of radius 2.0m. The magnitude of its velocity, its speed, is 15 m/s 1. What is the weight of an object (in Newtons) which has a mass of 45.8 kg? 2. What force must I exert to lift the above object off the ground? 3. A car with a mass of 1200 kg has an engine that can deliver a constant force of 25,000N. What would be the acceleration of the car? 4 Q12: A 50-kg box is hung from a 5-meter long, 200-kg horizontal pole as shown above. A wire is attached to prevent the sign from rotating. An object with uniform mass density is rotated about an axle, which may be in position A, B, C, or D. Rank the What is the angular acceleration experienced by a uniform solid disc of mass 2-kg and.

An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/ s to 8 m/s in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object. Answer We are given that Mass of object (m) = 100 kg Initial velocity (u) = 5 m/s Final velocity (ν) = 8 m/s Time = 6 sec Q: If Eren and his s kateboard actually had a mass of 40 kg instead of 50 kg, how much force would it take for him to accelerate at 0.8 m/s 2?. A: It would take only 32 N of force (40 kg × 0.8 m/s 2).. Summary. According to Newton's second law of motion, the acceleration of an object equals the net force acting on it divided by its mass, or a = F m.; This equation for acceleration can be. Mass is the total amount of matter in an object, measured in kilograms (kg). Force is the push or pull on an object, measured in newton (N). Acceleration is the rate of change in velocity experienced by an object, measured in meter per second squared (m/s2). The second law of Newton pioneered the equation to calculate acceleration B. the force on an object can be found by dividing its mass by is acceleration C. acceleration is inversely proportional to the mass and directly proportional to the net force D. when a force is applied on an object, there is an equal force applied by the object in the opposite direction 16. Newton's first law of motion states that ____

NCERT Class 9 Physics Force Numerical - FlexiPre

1. An object with a charge of -2.9 microC and a mass of .012 kg experiences an upward electric force, due to a uniform electric field, equal in magnitude to its weight. Part A: Find the magnitude of the electric field. Which I correctly calculated to be 4.1 x 10^4 N/C A small inspection car with a mass of 200 kg runs along the fixed overhead cable and is controlled by the attached cable at A. Determine the acceleration of the car when the control cable is horizontal and under a tension T = 2.4 kN. Also find the total force P exerted by the supporting cable on the wheels 10 A 1 kg object is located at a distance of 7.0 x108 m from the center of a larger object whose mass is 2.0 x 1030 kg. A What is the size of the force acting on the smaller object? B What is the size of the force acting on the larger object? C What is the acceleration of the smaller object when it is released Calculate the mass of the object. Solution: Given data: Acceleration of the object, a = 10 m/s 2 Force applied on the object, F net = 15 N Mass of the object, m =? According to Newton's second law formula, F net = ma m = F net / a m = 15 / 10 m = 1.5 kg Therefore, the mass of the object is 1.5 kg. Numerical 3

What is the acceleration of the object of force 200N and

5.2 Centripetal Acceleration In uniform circular motion, When a net external force acts on an object of mass m, the acceleration that results is The model airplane has a mass of 0.90 kg and moves at constant speed on a circle that is parallel to the ground Inertial mass is a measure of how difficult it is to change the velocity of an object. Example. Calculate the force needed to accelerate a 22 kg cheetah at 15 m/s²

1. A force of 50N act on the object of mass 20 kg. shown in the figure. Calculate the acceleration of the object in x and y directions. Ans: ax=2.165 ms-2; ay=1.25 ms-2. 2. A spider of mass 50 g is hanging on a string of a cob web as shown in the figure above. The objects are initially held at rest. If a third object 'Aith a mass of 0.30 kilogram is added on top of one of the .60-kilogram objects as shown and the objects are released, the nugnitude of the acceleration of the .30-kilogram object is nu)st nearly (A) 10.0 (B) 6.0 (C) 3.0 n/s: ) 2.0 (E) 1.0 nVs2 22 The pulley is a solid cylinder with mass M = 8.00 kg and radius r = 0.200 m. The block of mass m2 is allowed to drop, and the cord turns the pulley without slipping. (a) Why must the tension T2 be greater than the tension T1? (b) What is the acceleration of the system, assuming the pulley axis is frictionless? (c) Find the tensions T1 and T2 Defining the mass of an object as the quantity of matter it possesses is not a very good scientific definition. A better one can be found in Newton's second law of motion.If a constant force is applied to an object on a frictionless, horizontal surface, the object accelerates—its velocity increases uniformly with time.If a force twice as large is applied to the same object, its acceleration.

mass = force/acceleration here acceleration =a = (10-5)/1 = 5 m/s 2 so, mass = 200/5 kg = 40 kg 7) A mass of 1 kg is moving from east to west with a velocity of 10 m/s. A force is applied to it for 2 seconds and its velocity becomes 5 m/s The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The direction of the acceleration is in the direction of the net force acting on the object. ΣF is the vector sum of all forces acting on the body which we call the Net Force. m F a F m The total mass of loaded cart is 1.0 kg and its momentum is 2.0 kg•m/s. If the cart was instead loaded with three 0.5-kg bricks, then the total mass of the loaded cart would be 2.0 kg and its momentum would be 4.0 kg•m/s. A doubling of the mass results in a doubling of the momentum uniform disk of radius =0.280 m, as shown. The disk rotates without friction about a stationary horizontal axis that passes through the center of the disk. An object of mass =4.20 kg is suspended from the free end of the wire. The system is released from rest and the suspended object descends with constant acceleration